Home
Class 12
CHEMISTRY
The vapour pressure of a solvent is 60 t...

The vapour pressure of a solvent is 60 torr while that of its dilute solution is 52 torr. The mole fraction of the solvent is :

A

0.867

B

0.133

C

0.902

D

0.568

Text Solution

Verified by Experts

The correct Answer is:
A

`p^(@)=60` torr, `p_(s)=52` torr
`(p^(@)-p_(s))/(p^(@))=x`(solute)
`(60-52)/(60)=x` (solute)
or `x` (solute)`=0.133`
`x`(solvent)`=1-0.133=0.867`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level-I) (Basic conceptual Qs) (Colligative Properties)|38 Videos
  • SOLUTIONS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level-I) (Basic conceptual Qs) (Colligative Properties of Electrolyte Solutions)|17 Videos
  • SOLUTIONS

    MODERN PUBLICATION|Exercise Recent Examination Questions|13 Videos
  • REDOX REACTIONS

    MODERN PUBLICATION|Exercise Recent Examination Questions|6 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTION|15 Videos

Similar Questions

Explore conceptually related problems

At a certain temperature, the vapour pressure of pure ether is 640 mm and that of pure acetone is 280 mm . Calculate the mole fraction of each component in the vapour state if the mole fraction of ether in the solution is 0.50.

The vapour pressure of a pure liquid A is 40 mm Hg at 310 K . The vapour pressure of this liquid in a solution with liquid B is 32 mm Hg . The mole fraction of A in the solution, if it obeys Raoult's law, is:

The vapour pressure of a solvent decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of solute is 0.2 , what would be the mole fraction of solvent if the decrease in vapour pressure is 20 mm of Hg .

Calculate the vapour pressure of the solution. The molefraction of the solute is 0.25. The vapour pressure of the pure solvent is 0.8atm.

Benzene and toluene form nearly ideal solution. At 298 K , the vapour pressure of pure benzene is 150 torr and of pure toluence is 50 torr. Calculate the vapour pressure of the solution, containing equal weights of two substances at this temperature?

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

If P^(@) and P_(s) are vapour pressure of solvent and its solution, respectively, chi_(1) and chi_(2) are mole fractions of solvent and solute, respectively, then

Benzene and toluene form nearly ideal solutions. At 20^(@)C , the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20^(@)C for a solution containing 78 g of benzene and 46 g of toluene in torr is