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The vapour pressure of pure components A...

The vapour pressure of pure components A and B are 200 torr and 100 torr respectively. Assuming a solution of these components obeys Raoult's law, the mole fraction of component. A in vapour phase in equilibrium with a solution containing equimoles of A and B is :

A

0.22

B

0.33

C

0.67

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
C
`P_(A)=200xx0.5=100` torr
`P_(B)=100xx0.5=50` torr
`P_("(total)")=P_(A)+P_(B)=100+50=150` torr
Mole fraction of A in vapour phase
`=(100)/(150)=0.67`
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