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The molal cryoscopic for water is 1.86 "...

The molal cryoscopic for water is `1.86 "K mol"^(-1)`. When 3.42 g of sugar ( molar mass = 342) is dissolved in 100 g of water, the solution will freeze at

A

`1.86^(@)C`

B

`0.186^(@)C`

C

`-0.186^(@)C`

D

`0.914^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaT_(f)=(K_(f)xx W_(B)xx1000)/(W_(A)xxM_(B))`
`=(1.86xx3.42xx1000)/(100xx342)=0.186`
Freezing point of solution `=0-0.186`
`=-0.186^(@)C`
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