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If K(f) for water is 1.86^(@)C"mol"^(-1)...

If `K_(f)` for water is `1.86^(@)C"mol"^(-1)`, a 0.1 m solution of urea in water will have the freezing point of

A

`0.186^(@)C`

B

`1.86^(@)C`

C

`-0.186^(@)C`

D

`-0.372^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaT_(f)=K_(f)xx m=1.86xx0.1=0.186`
Freezing point of solution `=0-0.186`
`= - 0.186^(@)C`
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