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Six grams of urea ( molar mass = 60 ) ar...

Six grams of urea ( molar mass `= 60` ) are dissolved in 90 g of water. The relative lowering of vapour pressure is equal to

A

0.0196

B

0.06

C

0.01

D

0.0202

Text Solution

Verified by Experts

The correct Answer is:
A
Relative lowering of vapour pressure `=` Mole fraction of solute `(x_(B))`
`x_(B)=((6)/(60))/(6/60 +90/18)=0.0196`
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