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The molar elevation constant for water i...

The molar elevation constant for water is `0.52^(@)`. The elevation caused in the boiling point of water by dissolving 0.25 mole of a non-volatile solute in 250 g of water will be

A

`0.52^(@)C`

B

`0.052^(@)C`

C

`5.2^(@)C`

D

`52^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
Molality of solution `=(0.25)/(250)xx1000=1`
`DeltaT_(b)=K_(f)xx m = 0.52xx1=0.52^(@)C`
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