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6 grams of a substance 'A' dissolved in ...

6 grams of a substance 'A' dissolved in 100 g of water freezes at - `0.93^(@)C`. The molecular mass of 'A' is (`K_(f)=1.86 Km^(-1)`).

A

60

B

120

C

180

D

140

Text Solution

Verified by Experts

The correct Answer is:
B

`Delta T_(f)=0-(-0.93)=0.93`
`M_(B)=(K_(f)xx1000xx w_(B))/(w_(A)xx Delta T_(f))`
`=(1.86xx1000xx6)/(100 xx 0.93)=120`
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