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If 10.0 g of a non-electrolyte dissolved...

If 10.0 g of a non-electrolyte dissolved in 100 g of water lowers the freezing point of water by `1.86^(@)C`, the molar mass of the non-electrolyte is ( `K_(f)=1.86 Km^(-1)`)

A

`10.0`

B

100

C

1000

D

186

Text Solution

Verified by Experts

The correct Answer is:
B
`M_(B)=(K_(f)xx1000xx w_(B))/(w_(A) xx Delta T_(f))`
`=(1.86xx1000xx10.0)/(100xx1.86)=100`
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