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1.00 g of a non electrolyte solute ( mol...

1.00 g of a non electrolyte solute ( molar mass `250 " g mol"^(-1)`) was dissolved in 51.2 g of benzene. If the freezing point depression constant, `K_(f)` of benzene is `5*12` K kg `"mol"^(-1)`, the freezing point of benzene will be lowered by

A

0.3 K

B

0.5 K

C

0.2 K

D

0.4 K

Text Solution

Verified by Experts

The correct Answer is:
D
`Delta T_(f)=(K_(f)xx 1000 xx W_(2))/(M_(2)xxW_(1))`
`(5*12xx1000xx1)/(51*2xx250)=0*4`.
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