A 5% solution of sugarcane ( mol. wt. 342 ) is isotonic with 1% solution of X under similar conditions. The molecular mass of X is :

Options

A. 136.2
B. 68.4
C. 34.2
D. 171.2

Answer

B

Explanation

`pi_("sugarcane")=pi_(x)`
or `C_("sugarcane")=C_(x)`
`[(W_(B)xx1000)/(M_(B)xxV)]_("sugarcane")=[(W_(B)xx1000)/(M_(B)xxV)]_(x)`
`[(5xx1000)/(342xx100)]_("sugarcane")=[(1xx1000)/(M_(B)xx V)]_(x)`
`M_(B)" of " X = (1000xx100xx342)/(5xx1000xx100)`
`=68.4`