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If each side of a cube is decreased by 1...

If each side of a cube is decreased by 19%, then decrease in surface area is

A

0.4

B

0.384

C

0.35

D

0.3439

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The correct Answer is:
To solve the problem of finding the decrease in surface area of a cube when each side is decreased by 19%, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We need to find the decrease in surface area of a cube when each side is decreased by 19%. 2. **Define the Original Side Length**: Let the original side length of the cube be \( s \). 3. **Calculate the New Side Length**: If each side is decreased by 19%, the new side length \( s' \) can be calculated as: \[ s' = s - 0.19s = 0.81s \] 4. **Calculate the Original Surface Area**: The surface area \( A \) of a cube is given by the formula: \[ A = 6s^2 \] 5. **Calculate the New Surface Area**: The new surface area \( A' \) after the side length is decreased is: \[ A' = 6(s')^2 = 6(0.81s)^2 = 6 \times 0.6561s^2 = 3.9366s^2 \] 6. **Calculate the Decrease in Surface Area**: The decrease in surface area \( \Delta A \) can be found by subtracting the new surface area from the original surface area: \[ \Delta A = A - A' = 6s^2 - 3.9366s^2 = (6 - 3.9366)s^2 = 2.0634s^2 \] 7. **Calculate the Percentage Decrease in Surface Area**: The percentage decrease in surface area is given by: \[ \text{Percentage Decrease} = \left(\frac{\Delta A}{A}\right) \times 100 = \left(\frac{2.0634s^2}{6s^2}\right) \times 100 \] Simplifying this gives: \[ \text{Percentage Decrease} = \left(\frac{2.0634}{6}\right) \times 100 \approx 34.39\% \] ### Final Answer: The decrease in surface area is approximately **34.39%**.
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