Home
Class 11
MATHS
For a given distribution of marks mean i...

For a given distribution of marks mean is 35.16 and its standard deviation is 19.76. The coefficient of variation is :

A

`(19.76)/(35.16)xx10`

B

`(35.16)/(19.76)xx100`

C

`(19.76)/(35.16)`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the coefficient of variation (CV) for the given distribution of marks, we can follow these steps: ### Step 1: Understand the formula for Coefficient of Variation The coefficient of variation (CV) is calculated using the formula: \[ CV = \left( \frac{\text{Standard Deviation}}{\text{Mean}} \right) \times 100 \] ### Step 2: Identify the given values From the problem, we have: - Mean (μ) = 35.16 - Standard Deviation (σ) = 19.76 ### Step 3: Substitute the values into the formula Now, we will substitute the given values into the CV formula: \[ CV = \left( \frac{19.76}{35.16} \right) \times 100 \] ### Step 4: Calculate the fraction First, calculate the fraction: \[ \frac{19.76}{35.16} \approx 0.561 \] ### Step 5: Multiply by 100 Now, multiply the result by 100 to get the coefficient of variation: \[ CV \approx 0.561 \times 100 \approx 56.1 \] ### Final Answer Thus, the coefficient of variation is approximately **56.1%**. ---
Promotional Banner

Topper's Solved these Questions

  • STATISTICS

    MODERN PUBLICATION|Exercise Objective B(Fill in the Blanks)|6 Videos
  • STATISTICS

    MODERN PUBLICATION|Exercise Objective C(True/False)|3 Videos
  • STATISTICS

    MODERN PUBLICATION|Exercise Exercise 15(c ) (Long Answer Type Question - I)|8 Videos
  • SETS

    MODERN PUBLICATION|Exercise CHAPTER TEST 1|12 Videos
  • STRAIGHT LINES

    MODERN PUBLICATION|Exercise Chapter test|12 Videos

Similar Questions

Explore conceptually related problems

The standard deviation (sigma) of variate x is the square root of the A.M. of the squares of all deviations of x from the A.M. observations. If x_i//f_i , i=1,2,… n is a frequency distribution then sigma=sqrt(1/N Sigma_(i=1)^(n) f_i(x_i-barx)^2), N=Sigma_(i=1)^(n) f_i and variance is the square of standard deviation. Coefficient of dispersion is sigma/x and coefficient of variation is sigma/x xx 100 For a given distribution of marks mean is 35.16 and its standard deviation is 19.76 then coefficient of variation is

For a given distribution of marks, the mean is 35.16 and its standard deviation is 19.76. The coefficient of variation is

Find out standard deviation and coefficient of variation .

Calculate the standard deviation and coefficient of variation .

For a Binomial Distribution, mean is 16 and standard deviation is 2, then q is

Find out standard deviation and its coefficient of the following series: