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The solution of differential equation (1...

The solution of differential equation `(1+y^2)+((x-2e^tan^((-1)y))dy)/(dx)=0` is `(x-2)=k e^tan^((-1)y)` `x e^t a n-1y=e^2tan^((-4)y)+k` `x e^tan^((-1)y)=tan^(-1)y+k` `x e^2tan^((-1)y)=e^2tan^((-1)y)+k`

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