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A and B together can do a piece of work ...

A and B together can do a piece of work in 12 days, while B alone can finish it in 30 days. A alone can finish the work in

A

15 days

B

18 days

C

20 days

D

25 days

Text Solution

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The correct Answer is:
To solve the problem, we need to find out how many days A alone would take to finish the work. Let’s break it down step by step. ### Step 1: Determine the work rates of A and B 1. **Work done by A and B together in one day**: Since A and B together can complete the work in 12 days, their combined work rate is: \[ \text{Work rate of A and B} = \frac{1}{12} \text{ (work/day)} \] 2. **Work done by B alone in one day**: B can finish the work in 30 days, so B's work rate is: \[ \text{Work rate of B} = \frac{1}{30} \text{ (work/day)} \] ### Step 2: Calculate the work rate of A 3. **Work rate of A**: We know the combined work rate of A and B, and we can find A's work rate by subtracting B's work rate from the combined work rate: \[ \text{Work rate of A} = \text{Work rate of A and B} - \text{Work rate of B} \] \[ \text{Work rate of A} = \frac{1}{12} - \frac{1}{30} \] ### Step 3: Find a common denominator and perform the subtraction 4. **Finding a common denominator**: The least common multiple of 12 and 30 is 60. We convert the fractions: \[ \frac{1}{12} = \frac{5}{60}, \quad \frac{1}{30} = \frac{2}{60} \] Now we can subtract: \[ \text{Work rate of A} = \frac{5}{60} - \frac{2}{60} = \frac{3}{60} = \frac{1}{20} \text{ (work/day)} \] ### Step 4: Calculate the time taken by A to finish the work alone 5. **Time taken by A alone**: Since A's work rate is \(\frac{1}{20}\) work/day, the time taken by A to finish the work alone is the reciprocal of the work rate: \[ \text{Time taken by A} = \frac{1}{\text{Work rate of A}} = \frac{1}{\frac{1}{20}} = 20 \text{ days} \] ### Final Answer A alone can finish the work in **20 days**. ---
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ARIHANT SSC-WORK AND TIME -EXERCISE BASE LEVEL QUESTION
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