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In a school , mid day meal food is suffi...

In a school , mid day meal food is sufficient for 250 students for 33 days , if each student is given 125 g meals . 80 more students joined the school . If same of meal is given to each student , then the food will last

A

20 days

B

40 days

C

30 days

D

25 days

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The correct Answer is:
To solve the problem, we need to determine how many days the food will last after 80 more students join the school. Let's break it down step by step. ### Step 1: Calculate the total amount of food available. The food is sufficient for 250 students for 33 days, with each student receiving 125 grams of food. \[ \text{Total food} = \text{Number of students} \times \text{Amount of food per student} \times \text{Number of days} \] \[ \text{Total food} = 250 \times 125 \, \text{grams} \times 33 \, \text{days} \] \[ \text{Total food} = 250 \times 125 \times 33 \] ### Step 2: Calculate the total food in grams. Now, we can calculate the total food: \[ 250 \times 125 = 31250 \, \text{grams per day} \] \[ \text{Total food} = 31250 \times 33 = 1031250 \, \text{grams} \] ### Step 3: Determine the new total number of students. After 80 more students join, the total number of students becomes: \[ \text{New total students} = 250 + 80 = 330 \] ### Step 4: Set up the equation for the new scenario. Let \( X \) be the number of days the food will last for 330 students. The total food consumed by 330 students for \( X \) days is: \[ \text{Total food consumed} = \text{Number of students} \times \text{Amount of food per student} \times \text{Number of days} \] \[ \text{Total food consumed} = 330 \times 125 \times X \] ### Step 5: Equate the total food available to the total food consumed. Since the total food available remains the same, we can set up the equation: \[ 330 \times 125 \times X = 1031250 \] ### Step 6: Solve for \( X \). First, simplify the equation: \[ X = \frac{1031250}{330 \times 125} \] Now calculate \( 330 \times 125 \): \[ 330 \times 125 = 41250 \] Now substitute back into the equation: \[ X = \frac{1031250}{41250} \] Calculating \( X \): \[ X = 25 \, \text{days} \] ### Conclusion The food will last for **25 days** after the additional 80 students join the school. ---
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