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If x sin theta -y cos theta =sqrt(x^2 +y...

If `x sin theta -y cos theta =sqrt(x^2 +y^2) and cos^2 theta/a^2 +sin^2 theta/b^2 =1/(x^2 +y^2)`, then the correct relation is

A

`x^2/a^2 +y^2/b^2 =1`

B

`x^2/b^2 +y^2/a^2 =1`

C

`x^2/a^2 -y^2/b^2 =1`

D

`x^2/b^2 -y^2/a^2 =1`

Text Solution

Verified by Experts

The correct Answer is:
B
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