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The angles of depression of two ships fr...

The angles of depression of two ships from the top of a lighthouse are `45^@ and 30^@`. If the ships are 120 m apart, then find the height of the lighthouse.

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To find the height of the lighthouse given the angles of depression to two ships and the distance between the ships, we can follow these steps: ### Step 1: Understand the Problem We have a lighthouse and two ships. The angles of depression from the top of the lighthouse to the two ships are given as \(45^\circ\) and \(30^\circ\). The distance between the two ships is 120 meters. We need to find the height of the lighthouse. ### Step 2: Set Up the Diagram Let: - \(H\) = height of the lighthouse - \(X\) = horizontal distance from the base of the lighthouse to the first ship (the one at \(45^\circ\)) - \(X + 120\) = horizontal distance from the base of the lighthouse to the second ship (the one at \(30^\circ\)) ### Step 3: Apply Trigonometric Ratios Using the tangent function, we can set up equations based on the angles of depression. 1. For the first ship (angle of depression \(45^\circ\)): \[ \tan(45^\circ) = \frac{H}{X} \] Since \(\tan(45^\circ) = 1\), we have: \[ H = X \quad \text{(Equation 1)} \] 2. For the second ship (angle of depression \(30^\circ\)): \[ \tan(30^\circ) = \frac{H}{X + 120} \] Since \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\), we have: \[ \frac{1}{\sqrt{3}} = \frac{H}{X + 120} \] Rearranging gives: \[ H = \frac{(X + 120)}{\sqrt{3}} \quad \text{(Equation 2)} \] ### Step 4: Substitute Equation 1 into Equation 2 From Equation 1, we know \(X = H\). Substitute \(X\) in Equation 2: \[ H = \frac{(H + 120)}{\sqrt{3}} \] ### Step 5: Solve for H Multiply both sides by \(\sqrt{3}\): \[ H \sqrt{3} = H + 120 \] Rearranging gives: \[ H \sqrt{3} - H = 120 \] Factoring out \(H\): \[ H(\sqrt{3} - 1) = 120 \] Thus: \[ H = \frac{120}{\sqrt{3} - 1} \] ### Step 6: Rationalize the Denominator To rationalize the denominator: \[ H = \frac{120(\sqrt{3} + 1)}{(\sqrt{3} - 1)(\sqrt{3} + 1)} = \frac{120(\sqrt{3} + 1)}{3 - 1} = \frac{120(\sqrt{3} + 1)}{2} \] This simplifies to: \[ H = 60(\sqrt{3} + 1) \] ### Final Answer The height of the lighthouse is: \[ H = 60(\sqrt{3} + 1) \text{ meters} \] ---
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