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The angles of depression from the top of...

The angles of depression from the top of a light house of two boats are `45^@ and 30^@` towards the west. If the two boats are 5m apart, then the heighat of the light house is

A

(2.5V3 -1)m

B

2.5 (V3 -1)m

C

(2.5 V 3 + 1)m

D

2.5 (V3 + 1) m

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The correct Answer is:
To solve the problem, we will use the concept of angles of depression and some basic trigonometry. ### Step-by-step Solution: 1. **Understanding the Problem:** - We have a lighthouse from which the angles of depression to two boats are given as \(45^\circ\) and \(30^\circ\). - The distance between the two boats is \(5\) meters. 2. **Setting Up the Diagram:** - Let the height of the lighthouse be \(h\). - Let the distance from the base of the lighthouse to the first boat (where the angle of depression is \(45^\circ\)) be \(d_1\). - Let the distance from the base of the lighthouse to the second boat (where the angle of depression is \(30^\circ\)) be \(d_2\). - According to the problem, the distance between the two boats is \(d_2 - d_1 = 5\) meters. 3. **Using Trigonometry:** - For the first boat (angle of depression \(45^\circ\)): \[ \tan(45^\circ) = \frac{h}{d_1} \] Since \(\tan(45^\circ) = 1\), we have: \[ h = d_1 \] - For the second boat (angle of depression \(30^\circ\)): \[ \tan(30^\circ) = \frac{h}{d_2} \] Since \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\), we have: \[ h = \frac{d_2}{\sqrt{3}} \] 4. **Setting Up the Equation:** - From the two equations we derived: \[ d_1 = h \] \[ d_2 = h\sqrt{3} \] - Now substituting into the distance equation: \[ d_2 - d_1 = 5 \] \[ h\sqrt{3} - h = 5 \] \[ h(\sqrt{3} - 1) = 5 \] 5. **Solving for \(h\):** - Now, we can solve for \(h\): \[ h = \frac{5}{\sqrt{3} - 1} \] - To simplify, multiply the numerator and the denominator by the conjugate of the denominator: \[ h = \frac{5(\sqrt{3} + 1)}{(\sqrt{3} - 1)(\sqrt{3} + 1)} = \frac{5(\sqrt{3} + 1)}{3 - 1} = \frac{5(\sqrt{3} + 1)}{2} \] 6. **Final Calculation:** - Thus, the height of the lighthouse is: \[ h = \frac{5(\sqrt{3} + 1)}{2} \approx 5 \times 1.366 = 6.83 \text{ meters (approximately)} \] ### Final Answer: The height of the lighthouse is approximately \(6.83\) meters.
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