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The angle of elevation of the top of an ...

The angle of elevation of the top of an unfinished pillar at a point 150 m from its base is `30^@`. If the angle of elevation at the same point is to be `45^@`, then the pillar has to be raised to a height of how many metres?

A

59.4 m

B

61.4m

C

62.4m

D

63.4m

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The correct Answer is:
To solve the problem step by step, we will use trigonometric principles related to angles of elevation. ### Step 1: Understand the Problem We have an unfinished pillar and we want to find out how much higher it needs to be raised so that the angle of elevation from a point 150 meters away from its base changes from 30 degrees to 45 degrees. ### Step 2: Set Up the Diagram Let: - \( A \) be the base of the pillar. - \( B \) be the top of the unfinished pillar. - \( C \) be the point from which the angle of elevation is measured (150 m from the base). - The height of the unfinished pillar is \( h \). ### Step 3: Calculate the Height of the Pillar at 30 Degrees Using the angle of elevation of 30 degrees, we can use the tangent function: \[ \tan(30^\circ) = \frac{h}{150} \] We know that \( \tan(30^\circ) = \frac{1}{\sqrt{3}} \). Therefore, we can write: \[ \frac{1}{\sqrt{3}} = \frac{h}{150} \] ### Step 4: Solve for \( h \) Cross-multiplying gives: \[ h = 150 \cdot \frac{1}{\sqrt{3}} = \frac{150}{\sqrt{3}} \approx 86.6 \text{ m} \] ### Step 5: Calculate the Height of the Pillar at 45 Degrees Next, we consider the angle of elevation of 45 degrees: \[ \tan(45^\circ) = \frac{H}{150} \] Since \( \tan(45^\circ) = 1 \), we have: \[ 1 = \frac{H}{150} \] This implies: \[ H = 150 \text{ m} \] ### Step 6: Find the Increase in Height Now, we need to find out how much the height of the pillar needs to be increased: \[ \text{Increase in height} = H - h = 150 - \frac{150}{\sqrt{3}} \] ### Step 7: Simplify the Expression To simplify: \[ \text{Increase in height} = 150 \left(1 - \frac{1}{\sqrt{3}}\right) \] \[ = 150 \left(\frac{\sqrt{3} - 1}{\sqrt{3}}\right) \] ### Step 8: Rationalize the Denominator Multiply numerator and denominator by \( \sqrt{3} \): \[ = 150 \cdot \frac{\sqrt{3}(\sqrt{3} - 1)}{3} = 50\sqrt{3}(\sqrt{3} - 1) \] ### Step 9: Calculate the Final Value Now, substituting \( \sqrt{3} \approx 1.732 \): \[ \text{Increase in height} \approx 50 \cdot 1.732 \cdot (1.732 - 1) \approx 50 \cdot 1.732 \cdot 0.732 \approx 63.4 \text{ m} \] ### Conclusion Thus, the pillar needs to be raised by approximately **63.4 meters**. ---
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