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On walking 120 m towards a chimney in a ...

On walking 120 m towards a chimney in a horizonatal line through its base the angle of elevation of tip of the chimney changes from `30^@ " to " 45^@`. The height of the chimney is

A

120 m

B

60(V3 - 1)m

C

60(V3 + 1)m

D

None of these

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The correct Answer is:
To solve the problem, we will use the concept of right triangles and trigonometric ratios. ### Step-by-Step Solution: 1. **Understand the Situation**: - Let the height of the chimney be \( h \). - Initially, the observer is at point A, where the angle of elevation to the top of the chimney is \( 30^\circ \). - After walking 120 m towards the chimney, the observer reaches point B, where the angle of elevation is \( 45^\circ \). 2. **Set Up the Right Triangles**: - From point A (initial position), we can form a right triangle where: - The opposite side is the height of the chimney \( h \). - The adjacent side is the distance from point A to the base of the chimney, which we will denote as \( d \). - From point B (after walking 120 m), the distance to the base of the chimney is \( d - 120 \). 3. **Apply Trigonometric Ratios**: - For point A (angle of elevation \( 30^\circ \)): \[ \tan(30^\circ) = \frac{h}{d} \] We know that \( \tan(30^\circ) = \frac{1}{\sqrt{3}} \), so: \[ \frac{1}{\sqrt{3}} = \frac{h}{d} \implies h = \frac{d}{\sqrt{3}} \quad (1) \] - For point B (angle of elevation \( 45^\circ \)): \[ \tan(45^\circ) = \frac{h}{d - 120} \] Since \( \tan(45^\circ) = 1 \): \[ 1 = \frac{h}{d - 120} \implies h = d - 120 \quad (2) \] 4. **Equate the Two Expressions for \( h \)**: - From equations (1) and (2): \[ \frac{d}{\sqrt{3}} = d - 120 \] 5. **Solve for \( d \)**: - Rearranging gives: \[ d - \frac{d}{\sqrt{3}} = 120 \] \[ d \left(1 - \frac{1}{\sqrt{3}}\right) = 120 \] \[ d \left(\frac{\sqrt{3} - 1}{\sqrt{3}}\right) = 120 \] \[ d = \frac{120 \sqrt{3}}{\sqrt{3} - 1} \] 6. **Calculate \( h \)**: - Substitute \( d \) back into either equation (1) or (2) to find \( h \). Using equation (2): \[ h = d - 120 = \frac{120 \sqrt{3}}{\sqrt{3} - 1} - 120 \] 7. **Simplify to Find \( h \)**: - To simplify: \[ h = \frac{120 \sqrt{3} - 120(\sqrt{3} - 1)}{\sqrt{3} - 1} = \frac{120 \sqrt{3} - 120\sqrt{3} + 120}{\sqrt{3} - 1} = \frac{120}{\sqrt{3} - 1} \] - Rationalizing the denominator: \[ h = \frac{120(\sqrt{3} + 1)}{(\sqrt{3} - 1)(\sqrt{3} + 1)} = \frac{120(\sqrt{3} + 1)}{3 - 1} = 60(\sqrt{3} + 1) \] ### Final Answer: The height of the chimney is \( 60(\sqrt{3} + 1) \) meters.
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