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The concnetration of petrol is three dif...

The concnetration of petrol is three different mixtures (petrol and kerosene) is `1/2, 3/5` and `4/5` respectively. If 2 litres, 3 litres and 1 litre are taken from these different vessels and mixed. What is the ratio of petrol and Kerosone in the new mixture?

A

`4:5`

B

`3:2`

C

`3:5`

D

`2:3`

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The correct Answer is:
To solve the problem, we need to find the ratio of petrol to kerosene in the new mixture formed by mixing 2 litres from the first vessel, 3 litres from the second vessel, and 1 litre from the third vessel. ### Step-by-Step Solution: 1. **Identify the Concentrations:** - Vessel A (2 litres): Concentration of petrol = \( \frac{1}{2} \) - Vessel B (3 litres): Concentration of petrol = \( \frac{3}{5} \) - Vessel C (1 litre): Concentration of petrol = \( \frac{4}{5} \) 2. **Calculate the Amount of Petrol from Each Vessel:** - From Vessel A: \[ \text{Petrol from A} = 2 \text{ litres} \times \frac{1}{2} = 1 \text{ litre} \] - From Vessel B: \[ \text{Petrol from B} = 3 \text{ litres} \times \frac{3}{5} = \frac{9}{5} \text{ litres} = 1.8 \text{ litres} \] - From Vessel C: \[ \text{Petrol from C} = 1 \text{ litre} \times \frac{4}{5} = 0.8 \text{ litres} \] 3. **Total Amount of Petrol:** \[ \text{Total Petrol} = 1 + 1.8 + 0.8 = 3.6 \text{ litres} \] 4. **Calculate the Total Volume of the Mixture:** \[ \text{Total Volume} = 2 + 3 + 1 = 6 \text{ litres} \] 5. **Calculate the Amount of Kerosene:** - Since the total volume of the mixture is 6 litres and we have 3.6 litres of petrol, the amount of kerosene can be calculated as: \[ \text{Total Kerosene} = \text{Total Volume} - \text{Total Petrol} = 6 - 3.6 = 2.4 \text{ litres} \] 6. **Find the Ratio of Petrol to Kerosene:** \[ \text{Ratio of Petrol to Kerosene} = \frac{\text{Total Petrol}}{\text{Total Kerosene}} = \frac{3.6}{2.4} \] - Simplifying this ratio: \[ \frac{3.6}{2.4} = \frac{36}{24} = \frac{3}{2} \] ### Final Answer: The ratio of petrol to kerosene in the new mixture is \( 3:2 \).
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