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What number must be substracted from eac...

What number must be substracted from each of the numbers 53,21,41,,17 so that the remainders are in proportion?

A

1

B

3

C

5

D

None of these

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AI Generated Solution

The correct Answer is:
To solve the problem of finding the number that must be subtracted from each of the numbers 53, 21, 41, and 17 so that the remainders are in proportion, we can follow these steps: ### Step 1: Define the variable Let the number to be subtracted be \( x \). ### Step 2: Write the expressions for the remainders After subtracting \( x \) from each number, the remainders will be: - \( 53 - x \) - \( 21 - x \) - \( 41 - x \) - \( 17 - x \) ### Step 3: Set up the proportion According to the problem, the remainders must be in proportion. This can be expressed mathematically as: \[ \frac{53 - x}{21 - x} = \frac{41 - x}{17 - x} \] ### Step 4: Cross-multiply to eliminate the fractions Cross-multiplying gives us: \[ (53 - x)(17 - x) = (41 - x)(21 - x) \] ### Step 5: Expand both sides Expanding both sides: - Left side: \[ 53 \cdot 17 - 53x - 17x + x^2 = 901 - 70x + x^2 \] - Right side: \[ 41 \cdot 21 - 41x - 21x + x^2 = 861 - 62x + x^2 \] ### Step 6: Set the equation Now we have: \[ 901 - 70x + x^2 = 861 - 62x + x^2 \] ### Step 7: Simplify the equation Subtract \( x^2 \) from both sides: \[ 901 - 70x = 861 - 62x \] ### Step 8: Rearrange the equation Rearranging gives: \[ 901 - 861 = 70x - 62x \] \[ 40 = 8x \] ### Step 9: Solve for \( x \) Dividing both sides by 8: \[ x = 5 \] ### Conclusion The number that must be subtracted from each of the numbers 53, 21, 41, and 17 to make the remainders proportional is \( 5 \). ---
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ARIHANT SSC-RATIO, PROPORTION & VARIATION-EXERCISE (LEVEL 1)
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  9. The ratio of prices of Cello and Rotomac pens is 2000 were in the rati...

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  13. Rs. 171 are divided among four friends in the ratio of 1/3:1/4:1/5:1/6...

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  14. 10 years ago the age of Karishna was 1/3 rd of the age of Babita. 14 y...

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  15. The ratio of numerator to a denominator of a fraction is 1/5 when x an...

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  17. x varies directly as (y^(2)+z^(2)) At y=1 and z=2, the value of x is 1...

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  18. Weight of a sumo is jointly varies as his height and his age. When hei...

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