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Two alloys made up of copper and tin. Th...

Two alloys made up of copper and tin. The ratio of copper and tin in the first alloy is 1:3 in the second alloy it is 2:5 in what ratio the two alloys should be mixed to obtain a new alloy in which the ratio of tin and copper be 8:3?

A

`3:5`

B

`4:7`

C

`3:8`

D

`5:11`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of mixing two alloys made of copper and tin in the required ratio, we can follow these steps: ### Step 1: Understand the Ratios of Alloys The first alloy has a ratio of copper to tin as 1:3. This means: - For every 1 part of copper, there are 3 parts of tin. The second alloy has a ratio of copper to tin as 2:5. This means: - For every 2 parts of copper, there are 5 parts of tin. ### Step 2: Convert Ratios to Parts Let's denote the amounts of the first and second alloys as \( x \) and \( y \) respectively. From the first alloy: - Copper = \( \frac{1}{1+3} \cdot x = \frac{1}{4}x \) - Tin = \( \frac{3}{1+3} \cdot x = \frac{3}{4}x \) From the second alloy: - Copper = \( \frac{2}{2+5} \cdot y = \frac{2}{7}y \) - Tin = \( \frac{5}{2+5} \cdot y = \frac{5}{7}y \) ### Step 3: Set Up the Equation for the New Alloy We want the new alloy to have a ratio of tin to copper as 8:3. This means: - Total parts = 8 + 3 = 11 parts - Copper in the new alloy = \( \frac{3}{11} \) of the total - Tin in the new alloy = \( \frac{8}{11} \) of the total ### Step 4: Express the Total Copper and Tin in Terms of \( x \) and \( y \) The total copper in the new alloy can be expressed as: \[ \frac{1}{4}x + \frac{2}{7}y \] The total tin in the new alloy can be expressed as: \[ \frac{3}{4}x + \frac{5}{7}y \] ### Step 5: Set Up the Ratio Equation According to the desired ratio of tin to copper: \[ \frac{\frac{3}{4}x + \frac{5}{7}y}{\frac{1}{4}x + \frac{2}{7}y} = \frac{8}{3} \] ### Step 6: Cross-Multiply to Solve for \( x \) and \( y \) Cross-multiplying gives: \[ 3\left(\frac{3}{4}x + \frac{5}{7}y\right) = 8\left(\frac{1}{4}x + \frac{2}{7}y\right) \] Expanding both sides: \[ \frac{9}{4}x + \frac{15}{7}y = 2x + \frac{16}{7}y \] ### Step 7: Simplify the Equation Rearranging gives: \[ \frac{9}{4}x - 2x + \frac{15}{7}y - \frac{16}{7}y = 0 \] \[ \left(\frac{9}{4} - \frac{8}{4}\right)x + \left(\frac{15}{7} - \frac{16}{7}\right)y = 0 \] \[ \frac{1}{4}x - \frac{1}{7}y = 0 \] ### Step 8: Solve for the Ratio \( x:y \) Cross-multiplying gives: \[ 7x = 4y \implies \frac{x}{y} = \frac{4}{7} \] ### Final Answer The two alloys should be mixed in the ratio of **4:7**. ---
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