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The area of a right angled triangle is 2...

The area of a right angled triangle is 24 `cm^(2)` and the length of its hypotenuse is 10 cm. The length of the shorter leg is :

A

5 cm

B

4 cm

C

6 cm

D

3 cm

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The correct Answer is:
To find the length of the shorter leg of the right-angled triangle, we can use the area and the hypotenuse given in the problem. Let's denote the shorter leg as \( x \) and the longer leg as \( y \). ### Step-by-Step Solution: 1. **Use the Area Formula**: The area \( A \) of a right-angled triangle can be expressed as: \[ A = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times x \times y \] Given that the area is \( 24 \, \text{cm}^2 \), we can set up the equation: \[ \frac{1}{2} \times x \times y = 24 \] Multiplying both sides by 2 gives: \[ x \times y = 48 \quad \text{(Equation 1)} \] 2. **Use the Pythagorean Theorem**: According to the Pythagorean theorem, for a right-angled triangle: \[ x^2 + y^2 = \text{hypotenuse}^2 \] Given that the hypotenuse is \( 10 \, \text{cm} \), we have: \[ x^2 + y^2 = 10^2 = 100 \quad \text{(Equation 2)} \] 3. **Express \( y \) in terms of \( x \)**: From Equation 1, we can express \( y \) in terms of \( x \): \[ y = \frac{48}{x} \] 4. **Substitute \( y \) into Equation 2**: Substitute \( y \) into Equation 2: \[ x^2 + \left(\frac{48}{x}\right)^2 = 100 \] Simplifying this gives: \[ x^2 + \frac{2304}{x^2} = 100 \] 5. **Multiply through by \( x^2 \)** to eliminate the fraction: \[ x^4 - 100x^2 + 2304 = 0 \] Let \( z = x^2 \). Then we have: \[ z^2 - 100z + 2304 = 0 \] 6. **Use the quadratic formula**: The quadratic formula is given by: \[ z = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = -100, c = 2304 \): \[ z = \frac{100 \pm \sqrt{(-100)^2 - 4 \times 1 \times 2304}}{2 \times 1} \] \[ z = \frac{100 \pm \sqrt{10000 - 9216}}{2} \] \[ z = \frac{100 \pm \sqrt{784}}{2} \] \[ z = \frac{100 \pm 28}{2} \] This gives us two potential values for \( z \): \[ z = \frac{128}{2} = 64 \quad \text{or} \quad z = \frac{72}{2} = 36 \] 7. **Find \( x \)**: Since \( z = x^2 \): - If \( z = 64 \), then \( x = 8 \). - If \( z = 36 \), then \( x = 6 \). 8. **Determine the shorter leg**: The shorter leg \( x \) is \( 6 \, \text{cm} \) (since \( 8 \, \text{cm} \) would correspond to the longer leg \( y \)). ### Final Answer: The length of the shorter leg is \( 6 \, \text{cm} \).
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