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A cylindrical cirstern whose diameter is...

A cylindrical cirstern whose diameter is 21 cm is party filled with water. If a rectangular block of iron 14 cm in length , 10.5 cm in breadth and 11 cm in thickness is wholly immersed in water, by how many centimetres will the water level rise ?

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To solve the problem of how much the water level will rise in a cylindrical cistern when a rectangular block is immersed, we will follow these steps: ### Step 1: Calculate the Volume of the Rectangular Block The volume \( V \) of a rectangular block can be calculated using the formula: \[ V = \text{length} \times \text{breadth} \times \text{height} \] Given: - Length = 14 cm - Breadth = 10.5 cm - Height (thickness) = 11 cm Substituting the values: \[ V = 14 \, \text{cm} \times 10.5 \, \text{cm} \times 11 \, \text{cm} \] Calculating this: \[ V = 14 \times 10.5 = 147 \, \text{cm}^2 \] \[ V = 147 \times 11 = 1617 \, \text{cm}^3 \] ### Step 2: Calculate the Radius of the Cylindrical Cistern The diameter of the cylindrical cistern is given as 21 cm. Therefore, the radius \( r \) is: \[ r = \frac{\text{diameter}}{2} = \frac{21 \, \text{cm}}{2} = 10.5 \, \text{cm} \] ### Step 3: Set Up the Volume of the Cylinder The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] Where \( h \) is the height of the water level rise we want to find. ### Step 4: Equate the Volumes Since the volume of water displaced by the rectangular block is equal to the volume of water that rises in the cylindrical cistern: \[ \pi r^2 h = 1617 \, \text{cm}^3 \] Substituting \( r = 10.5 \, \text{cm} \): \[ \pi (10.5)^2 h = 1617 \] Calculating \( (10.5)^2 \): \[ (10.5)^2 = 110.25 \] Thus, the equation becomes: \[ \pi \times 110.25 \times h = 1617 \] ### Step 5: Solve for \( h \) Using \( \pi \approx \frac{22}{7} \): \[ \frac{22}{7} \times 110.25 \times h = 1617 \] To isolate \( h \): \[ h = \frac{1617 \times 7}{22 \times 110.25} \] Calculating the right side: \[ h = \frac{11319}{2425.5} \] Calculating \( 22 \times 110.25 = 2425.5 \): \[ h = \frac{11319}{2425.5} \approx 4.67 \, \text{cm} \] ### Final Answer The water level will rise by approximately **4.67 cm**. ---
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