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A rope by which a calf is tied is decrea...

A rope by which a calf is tied is decreased from 23 m to 12 m. What is the decrease in area to be grazed by it ?

A

`1110 m^(2) `

B

`1210 m^(2) `

C

`1120 m^(2) `

D

`1221 m^(2) `

Text Solution

AI Generated Solution

The correct Answer is:
To find the decrease in the area that the calf can graze when the length of the rope is decreased from 23 m to 12 m, we will follow these steps: ### Step 1: Calculate the area grazed with the original rope length (23 m) The area grazed by the calf when tied with a rope of length 23 m forms a circle. The formula for the area of a circle is given by: \[ \text{Area} = \pi r^2 \] Here, \( r = 23 \) m. \[ \text{Area}_1 = \pi (23)^2 = \frac{22}{7} \times 23 \times 23 \] Calculating \( 23^2 \): \[ 23^2 = 529 \] Now substituting back into the area formula: \[ \text{Area}_1 = \frac{22}{7} \times 529 \] ### Step 2: Calculate the area grazed with the new rope length (12 m) Now, we will calculate the area grazed when the rope length is decreased to 12 m. \[ \text{Area}_2 = \pi (12)^2 = \frac{22}{7} \times 12 \times 12 \] Calculating \( 12^2 \): \[ 12^2 = 144 \] Now substituting back into the area formula: \[ \text{Area}_2 = \frac{22}{7} \times 144 \] ### Step 3: Calculate the decrease in area To find the decrease in area, we subtract the area grazed with the new rope length from the area grazed with the original rope length: \[ \text{Decrease in Area} = \text{Area}_1 - \text{Area}_2 \] Substituting the areas we calculated: \[ \text{Decrease in Area} = \left(\frac{22}{7} \times 529\right) - \left(\frac{22}{7} \times 144\right) \] Factoring out \(\frac{22}{7}\): \[ \text{Decrease in Area} = \frac{22}{7} \left(529 - 144\right) \] Calculating \( 529 - 144 \): \[ 529 - 144 = 385 \] Now substituting back: \[ \text{Decrease in Area} = \frac{22}{7} \times 385 \] ### Step 4: Calculate the final decrease in area Now we will calculate: \[ \text{Decrease in Area} = \frac{22 \times 385}{7} \] Calculating \( 22 \times 385 \): \[ 22 \times 385 = 8470 \] Now dividing by 7: \[ \text{Decrease in Area} = \frac{8470}{7} = 1210 \text{ m}^2 \] ### Final Answer The decrease in the area that the calf can graze is **1210 m²**. ---
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ARIHANT SSC-MENSURATION-INTRODUCTORY EXERCISE- 10.4
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  2. The radius of a circle is increased by 2cm from 5 cm to 7 cm . What i...

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  3. If the circumference of a circle is increased by 20%, what will be ...

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  4. The area of a circular field is 124.74 hectares . The cost of fencing ...

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  5. Eldeco Housing Pvt. Ltd purchased a circular plot of land for Rs. 1584...

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  6. A figure consists of a square of side 'a' m with semicircle drawn on...

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  7. The length of a rope by which a buffalo must be tethered so that she m...

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  8. A circle with 7cm is segmented into six equal triangular areas as show...

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  9. In the following figure , the area in (cm^(2)) is :

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  10. If the piece of wire 25 cm long is bent into an arc of a circle subten...

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  11. Four horses are tethered at four corners of a square plot of 42 m so ...

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  12. The circumference of the following figure is :

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  13. The area of a minor sector subtending the central angle at the centr...

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  14. The area of a sector of a circle of radius 8 cm , formed by an arc of ...

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  15. How long will a man take to go, walking at 13.2 km/h , round a circula...

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  16. What is the radius of circular field whose area is equal to the sum o...

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  17. A rope by which a calf is tied is decreased from 23 m to 12 m. What i...

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  18. A wire is bent in the form of a square of side 66 m . It is cut and ag...

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  19. A wire is in the form of a circle of radius 42 m is cut and again ben...

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  20. If the driving wheel of a bicycle makes 560 revolutions in travelli...

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