A school hall has the dimensions 30 m , 12 m by 6m . Find the number of children who can be accommodated, if each child should get `8 m^(3)` of space :

Options

A. 240
B. 270
C. 250
D. 150

Answer

To solve the problem of how many children can be accommodated in the school hall, we will follow these steps:

### Step 1: Calculate the Volume of the Hall
The volume of a rectangular hall can be calculated using the formula:
\[ \text{Volume} = \text{Length} \times \text{Breadth} \times \text{Height} \]
Given the dimensions of the hall:
- Length = 30 m
- Breadth = 12 m
- Height = 6 m

Substituting the values:
\[ \text{Volume} = 30 \, \text{m} \times 12 \, \text{m} \times 6 \, \text{m} \]
\[ \text{Volume} = 2160 \, \text{m}^3 \]

### Step 2: Determine the Volume Required per Child
According to the problem, each child requires 8 m³ of space.

### Step 3: Calculate the Number of Children that Can be Accommodated
To find the number of children that can be accommodated, we divide the total volume of the hall by the volume required per child:
\[ \text{Number of Children} = \frac{\text{Total Volume of Hall}}{\text{Volume per Child}} \]
Substituting the values:
\[ \text{Number of Children} = \frac{2160 \, \text{m}^3}{8 \, \text{m}^3} \]
\[ \text{Number of Children} = 270 \]

### Conclusion
The number of children that can be accommodated in the hall is **270**.

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