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The lateral surface area of a cylinder i...

The lateral surface area of a cylinder is ` 1056 cm^(2)` and its height is 16 cm. What is its volume ?

A

`5566 cm^(3) `

B

`4455 cm^(3) `

C

`5544 cm^(3) `

D

none of these

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The correct Answer is:
To find the volume of the cylinder given its lateral surface area and height, we can follow these steps: ### Step 1: Understand the formula for lateral surface area The lateral surface area (LSA) of a cylinder is given by the formula: \[ \text{LSA} = 2 \pi r h \] where \( r \) is the radius and \( h \) is the height of the cylinder. ### Step 2: Substitute the known values into the formula We know the lateral surface area is \( 1056 \, \text{cm}^2 \) and the height \( h \) is \( 16 \, \text{cm} \). Substituting these values into the formula gives: \[ 1056 = 2 \pi r \times 16 \] ### Step 3: Simplify the equation We can simplify the equation: \[ 1056 = 32 \pi r \] Now, substituting \( \pi \) with \( \frac{22}{7} \): \[ 1056 = 32 \times \frac{22}{7} \times r \] ### Step 4: Solve for \( r \) To isolate \( r \), we first multiply both sides by \( 7 \): \[ 1056 \times 7 = 32 \times 22 \times r \] Calculating \( 1056 \times 7 \): \[ 7392 = 704 r \] Now, divide both sides by \( 704 \): \[ r = \frac{7392}{704} = 10.5 \, \text{cm} \] ### Step 5: Calculate the volume of the cylinder The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] Substituting the values of \( r \) and \( h \): \[ V = \frac{22}{7} \times (10.5)^2 \times 16 \] ### Step 6: Calculate \( (10.5)^2 \) Calculating \( (10.5)^2 \): \[ (10.5)^2 = 110.25 \] ### Step 7: Substitute back into the volume formula Now substituting back into the volume formula: \[ V = \frac{22}{7} \times 110.25 \times 16 \] ### Step 8: Simplify the calculation Calculating \( \frac{22 \times 110.25 \times 16}{7} \): First, calculate \( 110.25 \times 16 = 1764 \): \[ V = \frac{22 \times 1764}{7} \] Calculating \( 22 \times 1764 = 38808 \): \[ V = \frac{38808}{7} = 5544 \, \text{cm}^3 \] ### Final Answer The volume of the cylinder is: \[ \boxed{5544 \, \text{cm}^3} \]
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