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The amount of concrete required to build...

The amount of concrete required to build a cylindrical pillar whose base has a perimeter of 8.8 m and whose curved surface area is `17.6 m^(2)` :

A

`12.32 m^(3) `

B

`12.23 m^(3) `

C

`9.235 m^(3) `

D

`8.88 m^(3) `

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The correct Answer is:
To find the amount of concrete required to build a cylindrical pillar, we need to calculate the volume of the cylinder using the given perimeter of the base and the curved surface area. Here’s a step-by-step solution: ### Step 1: Find the radius of the base The perimeter (circumference) of the base of the cylinder is given as 8.8 m. The formula for the perimeter of a circle is: \[ \text{Perimeter} = 2\pi r \] Setting this equal to the given perimeter: \[ 2\pi r = 8.8 \] Using \(\pi \approx \frac{22}{7}\): \[ 2 \times \frac{22}{7} \times r = 8.8 \] Now, simplify: \[ \frac{44}{7} r = 8.8 \] To isolate \(r\), multiply both sides by \(\frac{7}{44}\): \[ r = 8.8 \times \frac{7}{44} \] Calculating this gives: \[ r = \frac{8.8 \times 7}{44} = \frac{61.6}{44} = 1.4 \text{ m} \] ### Step 2: Find the height of the cylinder The curved surface area (CSA) of the cylinder is given as 17.6 m². The formula for the curved surface area is: \[ \text{CSA} = 2\pi rh \] Setting this equal to the given CSA: \[ 2\pi rh = 17.6 \] Substituting the value of \(\pi\) and \(r\): \[ 2 \times \frac{22}{7} \times 1.4 \times h = 17.6 \] Simplifying: \[ \frac{44}{7} \times 1.4 \times h = 17.6 \] Calculating \(44 \times 1.4\): \[ \frac{61.6}{7} h = 17.6 \] Now, multiply both sides by 7: \[ 61.6h = 123.2 \] To find \(h\), divide both sides by 61.6: \[ h = \frac{123.2}{61.6} = 2 \text{ m} \] ### Step 3: Calculate the volume of the cylinder The volume \(V\) of the cylinder is given by the formula: \[ V = \pi r^2 h \] Substituting the values of \(\pi\), \(r\), and \(h\): \[ V = \frac{22}{7} \times (1.4)^2 \times 2 \] Calculating \(1.4^2\): \[ 1.4^2 = 1.96 \] Now substituting this value: \[ V = \frac{22}{7} \times 1.96 \times 2 \] Calculating the volume: \[ V = \frac{22 \times 1.96 \times 2}{7} = \frac{86.56}{7} = 12.36 \text{ m}^3 \] ### Conclusion The amount of concrete required to build the cylindrical pillar is approximately **12.36 m³**. ---
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ARIHANT SSC-MENSURATION-INTRODUCTORY EXERCISE- 10.6
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  7. If the volume and curved surface area of a cylinder are 269.5 cm^(3)...

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  8. If the curved surface area of a cylinder is 1320 cm^(2) and its base r...

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  9. The ratio between the radius of the base and the height of a cylindric...

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  10. If the ratio of total surface area to the curved surface area of a cyl...

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  16. The ratio of heights of two cylinders is 3:2 and the ratio of their ra...

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