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The ratio between the radius of the base...

The ratio between the radius of the base and the height of a cylindrical pillar is 3:4 . If its volume is ` 4851 m^(3) `, the curved surface area of the pillar is :

A

`924 m^(2) `

B

`1617 m^(2) `

C

`425 m^(2)`

D

none of these

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The correct Answer is:
To find the curved surface area of a cylindrical pillar given the ratio of the radius to height and the volume, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Ratio**: The ratio of the radius (r) to the height (h) of the cylindrical pillar is given as 3:4. Let the radius be \( r = 3x \) and the height be \( h = 4x \). 2. **Volume of the Cylinder**: The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] We know the volume is \( 4851 \, m^3 \). Substituting the values of \( r \) and \( h \): \[ 4851 = \pi (3x)^2 (4x) \] 3. **Substituting Values**: Substitute \( \pi \) with \( \frac{22}{7} \): \[ 4851 = \frac{22}{7} (3x)^2 (4x) \] Simplifying further: \[ 4851 = \frac{22}{7} \cdot 9x^2 \cdot 4x \] \[ 4851 = \frac{22 \cdot 36x^3}{7} \] 4. **Cross Multiplying**: To eliminate the fraction, cross-multiply: \[ 4851 \cdot 7 = 22 \cdot 36x^3 \] \[ 33957 = 792x^3 \] 5. **Solving for \( x^3 \)**: Divide both sides by 792: \[ x^3 = \frac{33957}{792} \] Calculating the right-hand side: \[ x^3 = 42.875 \] 6. **Finding \( x \)**: Take the cube root of both sides: \[ x = \sqrt[3]{42.875} \approx 3.5 \, m \] 7. **Finding Radius and Height**: Now, substitute \( x \) back to find the radius and height: \[ r = 3x = 3 \cdot 3.5 = 10.5 \, m \] \[ h = 4x = 4 \cdot 3.5 = 14 \, m \] 8. **Curved Surface Area of the Cylinder**: The formula for the curved surface area (CSA) of a cylinder is: \[ CSA = 2\pi rh \] Substituting the values of \( r \) and \( h \): \[ CSA = 2 \cdot \frac{22}{7} \cdot 10.5 \cdot 14 \] 9. **Calculating CSA**: Simplifying the expression: \[ CSA = 2 \cdot \frac{22}{7} \cdot 10.5 \cdot 14 = 2 \cdot \frac{22 \cdot 10.5 \cdot 14}{7} \] \[ = 2 \cdot \frac{3084}{7} = 2 \cdot 440.5714 \approx 924 \, m^2 \] ### Final Answer: The curved surface area of the cylindrical pillar is \( 924 \, m^2 \). ---
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