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The radius of base and the volume of a ...

The radius of base and the volume of a right circular cone are doubled. The ratio of the length of the larger cone to that of the smaller cone is :

A

`1:4`

B

`1:2`

C

`2:1`

D

`4:1`

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The correct Answer is:
To solve the problem, we need to find the ratio of the lengths (heights) of two cones: the smaller cone and the larger cone, given that the radius of the base and the volume of the cone are both doubled. ### Step-by-Step Solution: 1. **Define the dimensions of the smaller cone:** - Let the radius of the base of the smaller cone be \( r \). - Let the height of the smaller cone be \( h \). 2. **Calculate the volume of the smaller cone:** - The formula for the volume \( V \) of a right circular cone is given by: \[ V = \frac{1}{3} \pi r^2 h \] - Therefore, the volume of the smaller cone is: \[ V_{\text{small}} = \frac{1}{3} \pi r^2 h \] 3. **Determine the dimensions of the larger cone:** - According to the problem, the radius of the base of the larger cone is doubled: \[ \text{Radius of larger cone} = 2r \] - The volume of the larger cone is also doubled: \[ V_{\text{large}} = 2 \times V_{\text{small}} = 2 \left( \frac{1}{3} \pi r^2 h \right) = \frac{2}{3} \pi r^2 h \] 4. **Calculate the volume of the larger cone using its dimensions:** - The volume of the larger cone can also be expressed as: \[ V_{\text{large}} = \frac{1}{3} \pi (2r)^2 H \] - Simplifying this gives: \[ V_{\text{large}} = \frac{1}{3} \pi (4r^2) H = \frac{4}{3} \pi r^2 H \] 5. **Set the two expressions for the volume of the larger cone equal to each other:** - From the previous steps, we have: \[ \frac{2}{3} \pi r^2 h = \frac{4}{3} \pi r^2 H \] 6. **Cancel out common terms:** - We can cancel \( \frac{1}{3} \pi r^2 \) from both sides (assuming \( r \neq 0 \)): \[ 2h = 4H \] 7. **Solve for the ratio of heights:** - Rearranging gives: \[ H = \frac{2h}{4} = \frac{h}{2} \] - Therefore, the ratio of the height of the larger cone \( H \) to the height of the smaller cone \( h \) is: \[ \frac{H}{h} = \frac{h/2}{h} = \frac{1}{2} \] 8. **Final ratio:** - The ratio of the length (height) of the larger cone to that of the smaller cone is: \[ \text{Ratio} = \frac{H}{h} = 2:1 \] ### Conclusion: The ratio of the length of the larger cone to that of the smaller cone is \( 2:1 \).
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