Home
Class 14
MATHS
Altitude and base of a right angle trian...

Altitude and base of a right angle triangle are (x+2) and (2x+3) ( in cm ). If the area of the triangle be 60 ` cm^(2)` , the length of the hypotenuse is :

A

21 cm

B

13 cm

C

17 cm

D

15 cm

Text Solution

AI Generated Solution

The correct Answer is:
To find the length of the hypotenuse of a right-angled triangle with given altitude and base, we can follow these steps: ### Step 1: Write down the formula for the area of a triangle. The area \( A \) of a triangle is given by the formula: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] ### Step 2: Substitute the given values into the area formula. Here, the altitude (height) is \( (x + 2) \) cm and the base is \( (2x + 3) \) cm. The area is given as 60 cm². Thus, we can set up the equation: \[ \frac{1}{2} \times (2x + 3) \times (x + 2) = 60 \] ### Step 3: Simplify the equation. Multiply both sides by 2 to eliminate the fraction: \[ (2x + 3)(x + 2) = 120 \] ### Step 4: Expand the left side of the equation. Using the distributive property (FOIL method): \[ 2x^2 + 4x + 3x + 6 = 120 \] Combine like terms: \[ 2x^2 + 7x + 6 = 120 \] ### Step 5: Move all terms to one side to form a quadratic equation. Subtract 120 from both sides: \[ 2x^2 + 7x + 6 - 120 = 0 \] This simplifies to: \[ 2x^2 + 7x - 114 = 0 \] ### Step 6: Solve the quadratic equation using the quadratic formula. The quadratic formula is: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 2 \), \( b = 7 \), and \( c = -114 \). First, calculate the discriminant: \[ b^2 - 4ac = 7^2 - 4 \times 2 \times (-114) = 49 + 912 = 961 \] Now, substitute into the quadratic formula: \[ x = \frac{-7 \pm \sqrt{961}}{2 \times 2} \] Since \( \sqrt{961} = 31 \): \[ x = \frac{-7 \pm 31}{4} \] Calculating the two possible values for \( x \): 1. \( x = \frac{24}{4} = 6 \) 2. \( x = \frac{-38}{4} \) (not valid since \( x \) must be positive) Thus, \( x = 6 \). ### Step 7: Calculate the base and height. Substituting \( x = 6 \) back into the expressions for base and height: - Height: \( x + 2 = 6 + 2 = 8 \) cm - Base: \( 2x + 3 = 2(6) + 3 = 12 + 3 = 15 \) cm ### Step 8: Use the Pythagorean theorem to find the hypotenuse. The Pythagorean theorem states: \[ \text{hypotenuse}^2 = \text{base}^2 + \text{height}^2 \] Substituting the values: \[ \text{hypotenuse}^2 = 15^2 + 8^2 = 225 + 64 = 289 \] Taking the square root: \[ \text{hypotenuse} = \sqrt{289} = 17 \text{ cm} \] ### Final Answer: The length of the hypotenuse is \( 17 \) cm. ---
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    ARIHANT SSC|Exercise EXERCISE (LEVEL 2)|68 Videos
  • MENSURATION

    ARIHANT SSC|Exercise TEST OF YOUR LEARNING|18 Videos
  • MENSURATION

    ARIHANT SSC|Exercise EXERCISE (MISCELLANEOUS)|59 Videos
  • LOGARITHM

    ARIHANT SSC|Exercise EXERCISE LEVEL 2|19 Videos
  • MIXED GRAPH

    ARIHANT SSC|Exercise Higher Skill Level Questions|15 Videos

Similar Questions

Explore conceptually related problems

The sides of a right-angied triangle forming right angle are in the ratio 5: 12. If the area of the triangle is 270 cm^2 , then the length of the hypotenuse is

The length of the sides forming right angle of a right angled triangle are 5x and (3x-1)cm. If the area of the triangle is 60cm^(2), find its hypotenuse.

The sides of a right angled triangle containing the right angle are 4x cm and (2x-1) cm. If the area of the triangle is 30cm^(2) calculate the lengths of its sides.

The base of a right triangle is 48 cm and its hypotenuse is 50 cm long. The area of the triangle is

An isosceles right triangle has area 8 cm^(2) . The length of its hypotenuse is

If the perimeter of a right-angled triangle is 56 cm and area of the triangle is 84 sq. cm, then the length of the hypotenuse is (in cm)

If the two legs of a right-angled triangle are 3cm" and "4cm ,find the area of the triangle. Find the length of the base of a triangle

The height and base of a right angled triangle are 24cm and 18cm , find the length of its hypotenuse.

ARIHANT SSC-MENSURATION-EXERCISE (LEVEL 1)
  1. A square and rhombus have the same base . If the rhombus is inclined a...

    Text Solution

    |

  2. If the area of a square is 400 m sq, what will be the sides and perime...

    Text Solution

    |

  3. Altitude and base of a right angle triangle are (x+2) and (2x+3) ( in ...

    Text Solution

    |

  4. Find the area of a regular octagon with each side 'a' cm :

    Text Solution

    |

  5. ABCD is a square , 4 equal circles are just touching each other whose ...

    Text Solution

    |

  6. ABCD is a trapezium , in which AD||BC, E and F are the mid-point of A...

    Text Solution

    |

  7. A right circular cone resting on its base is cut at (4)/(5)th its heig...

    Text Solution

    |

  8. l,b are the length and breadth of a rectangle respectively . If the pe...

    Text Solution

    |

  9. In the adjoining figure ABC is an equilateral triangle and C is the ce...

    Text Solution

    |

  10. The length of a rectangle is increased by 10% while its breadth is dec...

    Text Solution

    |

  11. An acute angle made by a side of parallelogram with other pair of para...

    Text Solution

    |

  12. A solid sphere is melted and recast into a right circular cone with a ...

    Text Solution

    |

  13. In the given figure there are 3 semicircles , the radii of each smalle...

    Text Solution

    |

  14. A rectangular grass plot 80 m xx 60 m has two roads, each 10 m wide, r...

    Text Solution

    |

  15. There are two rectangular fields of same area. The length of first rec...

    Text Solution

    |

  16. In the adjoining figure ACB is a quadrant with radius 'a'. A semicir...

    Text Solution

    |

  17. Ravi made an error of 5% in excess while measuring the length of recta...

    Text Solution

    |

  18. In the adjoining figure the cross-section of a swimming pool is shown ...

    Text Solution

    |

  19. The cost of fencing a circular field at the rate of Rs 25 per meter is...

    Text Solution

    |

  20. An equilateral triangle is cut from its three vertices to form a regu...

    Text Solution

    |