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A solid sphere is melted and recast into...

A solid sphere is melted and recast into a right circular cone with a base radius equal to the radius of the sphere . What is the ratio of the height and radius of the cone so formed ?

A

`4:3`

B

`2:3`

C

`3:4`

D

none of these

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the height of the cone to the radius of the cone formed when a solid sphere is melted and recast into a right circular cone. ### Step-by-Step Solution: 1. **Identify the Variables**: - Let the radius of the sphere be \( r \). - Since the radius of the cone is equal to the radius of the sphere, the radius of the cone \( R = r \). - Let the height of the cone be \( h \). 2. **Volume of the Sphere**: - The formula for the volume of a sphere is given by: \[ V_{sphere} = \frac{4}{3} \pi r^3 \] 3. **Volume of the Cone**: - The formula for the volume of a cone is given by: \[ V_{cone} = \frac{1}{3} \pi R^2 h \] - Since \( R = r \), we can substitute \( R \) in the volume formula of the cone: \[ V_{cone} = \frac{1}{3} \pi r^2 h \] 4. **Equate the Volumes**: - Since the volume of the sphere is equal to the volume of the cone (as the sphere is melted and recast into the cone), we have: \[ \frac{4}{3} \pi r^3 = \frac{1}{3} \pi r^2 h \] 5. **Cancel Common Terms**: - We can cancel \( \frac{1}{3} \pi \) from both sides: \[ 4r^3 = r^2 h \] 6. **Solve for Height \( h \)**: - Divide both sides by \( r^2 \) (assuming \( r \neq 0 \)): \[ h = \frac{4r^3}{r^2} = 4r \] 7. **Find the Ratio of Height to Radius**: - The ratio of the height of the cone \( h \) to the radius of the cone \( R \) is: \[ \text{Ratio} = \frac{h}{R} = \frac{4r}{r} = 4 \] ### Final Answer: The ratio of the height to the radius of the cone is \( 4:1 \). ---
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