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The average revenues of 11 consecutive y...

The average revenues of 11 consecutive years of a company is rs.77 lakhs. if the average of first 6 years is rs.72 lakhs and that of last 6 years is rs.84 lakhs. What is the revenue for the sisth year.

A

a. 91lakhs

B

b. 87lakhs

C

c. 89lakhs

D

d.none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the revenue for the 6th year based on the given averages, we can follow these steps: ### Step-by-Step Solution: 1. **Calculate the total revenue for 11 years:** \[ \text{Total Revenue for 11 years} = \text{Average Revenue} \times \text{Number of Years} = 77 \text{ lakhs} \times 11 = 847 \text{ lakhs} \] 2. **Calculate the total revenue for the first 6 years:** \[ \text{Total Revenue for first 6 years} = \text{Average Revenue} \times \text{Number of Years} = 72 \text{ lakhs} \times 6 = 432 \text{ lakhs} \] 3. **Calculate the total revenue for the last 6 years:** \[ \text{Total Revenue for last 6 years} = \text{Average Revenue} \times \text{Number of Years} = 84 \text{ lakhs} \times 6 = 504 \text{ lakhs} \] 4. **Add the total revenues of the first 6 years and the last 6 years:** \[ \text{Total Revenue for first 6 years} + \text{Total Revenue for last 6 years} = 432 \text{ lakhs} + 504 \text{ lakhs} = 936 \text{ lakhs} \] 5. **Since the 6th year is included in both the first 6 years and the last 6 years, we need to subtract the total revenue of 11 years from the combined total of the first and last 6 years to find the revenue for the 6th year:** \[ \text{Revenue for 6th year} = (\text{Total Revenue for first 6 years} + \text{Total Revenue for last 6 years}) - \text{Total Revenue for 11 years} \] \[ \text{Revenue for 6th year} = 936 \text{ lakhs} - 847 \text{ lakhs} = 89 \text{ lakhs} \] ### Final Answer: The revenue for the 6th year is **89 lakhs**. ---
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