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In an examination, 30% and 35% students ...

In an examination, 30% and 35% students failed in physics and chemistry respectively while 27% students failed in both the subjects. If the number of students passing the examination is 248, find the total number of students who appeared in the examination.

A

a. 500

B

b. 400

C

c. 450

D

d. none of these

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The correct Answer is:
To solve the problem step by step, we can follow these calculations: ### Step 1: Understand the Problem We know that: - 30% of students failed in Physics. - 35% of students failed in Chemistry. - 27% of students failed in both subjects. - The number of students who passed is 248. ### Step 2: Calculate Total Percentage of Students Who Failed To find the total percentage of students who failed in at least one subject, we can use the principle of inclusion-exclusion: - Let \( P \) be the percentage of students who failed in Physics. - Let \( C \) be the percentage of students who failed in Chemistry. - Let \( B \) be the percentage of students who failed in both subjects. Using the formula: \[ \text{Total failed} = P + C - B \] Substituting the values: \[ \text{Total failed} = 30\% + 35\% - 27\% = 38\% \] ### Step 3: Calculate the Percentage of Students Who Passed The percentage of students who passed the examination can be calculated as: \[ \text{Percentage passed} = 100\% - \text{Total failed} \] Substituting the value we found: \[ \text{Percentage passed} = 100\% - 38\% = 62\% \] ### Step 4: Set Up the Equation We know that 62% of the total number of students equals 248 (the number of students who passed): \[ 62\% \text{ of Total Students} = 248 \] Let \( x \) be the total number of students. We can write the equation as: \[ 0.62x = 248 \] ### Step 5: Solve for Total Students To find \( x \), we divide both sides by 0.62: \[ x = \frac{248}{0.62} \] Calculating this gives: \[ x = 400 \] ### Step 6: Conclusion The total number of students who appeared in the examination is **400**. ---
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ARIHANT SSC-SEQUENCE, SERIES & PROGRESSIONS-Final Round
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