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If a,b,c are in A.P. b, c,d are in G.P. ...

If a,b,c are in A.P. b, c,d are in G.P. and c,d,e are in H.P., then which one of the following is true :

A

`2c=a+e`

B

`ae = c^2`

C

`c=(2ae)/(a+e)`

D

`ab=de`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the relationships between the terms given in the question. ### Step 1: Understanding the relationships We have three sets of terms: 1. \( a, b, c \) are in Arithmetic Progression (A.P.) 2. \( b, c, d \) are in Geometric Progression (G.P.) 3. \( c, d, e \) are in Harmonic Progression (H.P.) ### Step 2: Expressing the conditions mathematically 1. Since \( a, b, c \) are in A.P., we can express this as: \[ 2b = a + c \quad \Rightarrow \quad b = \frac{a + c}{2} \] 2. Since \( b, c, d \) are in G.P., we can express this as: \[ c^2 = bd \] 3. Since \( c, d, e \) are in H.P., we can express this as: \[ d = \frac{2ce}{c + e} \] ### Step 3: Substituting the expressions Now, we will substitute the expression for \( b \) into the G.P. condition and the expression for \( d \) into the H.P. condition. From the G.P. condition: \[ c^2 = b \cdot d \] Substituting \( b \): \[ c^2 = \left(\frac{a + c}{2}\right) d \] From the H.P. condition: \[ d = \frac{2ce}{c + e} \] Substituting this into the G.P. condition: \[ c^2 = \left(\frac{a + c}{2}\right) \left(\frac{2ce}{c + e}\right) \] ### Step 4: Simplifying the equation Now, simplifying the equation: \[ c^2 = \frac{(a + c)ce}{c + e} \] Cross-multiplying gives: \[ c^2(c + e) = (a + c)ce \] Expanding both sides: \[ c^3 + c^2e = ace + c^2e \] Cancelling \( c^2e \) from both sides: \[ c^3 = ace \] ### Step 5: Concluding the relationships From the equation \( c^3 = ace \), we can rearrange it to: \[ c^2 = ae \] This indicates that \( a, c, e \) are in G.P. (since \( c^2 = ae \) is the condition for three numbers to be in G.P.). ### Final Answer Thus, we conclude that \( a, c, e \) are in Geometric Progression (G.P.). ---
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