How much current flows through a `2kOmega` resistor when a potential difference of 4V is applied across its ends?

Explanation

To find the current flowing through a 2 kΩ resistor when a potential difference of 4 V is applied, we can use Ohm's Law, which states:

\[ V = I \times R \]

Where:
- \( V \) is the potential difference (in volts),
- \( I \) is the current (in amperes),
- \( R \) is the resistance (in ohms).
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