How much current is flowing through a `1kOmega` resistor when a potential difference of 2 V is applied across its end ?

Options

A. `2muA`
B. 2mA
C. 2A
D. 1A

Answer

To find the current flowing through a 1 kΩ resistor when a potential difference of 2 V is applied across its ends, we can use Ohm's Law, which states:

\[ V = I \times R \]

Where:
- \( V \) is the potential difference (in volts),
- \( I \) is the current (in amperes),
- \( R \) is the resistance (in ohms).

### Step-by-Step Solution:

1. **Identify the given values**:
- Potential difference, \( V = 2 \, \text{V} \)
- Resistance, \( R = 1 \, \text{k}\Omega = 1000 \, \Omega \)

2. **Rearrange Ohm's Law to solve for current \( I \)**:
\[ I = \frac{V}{R} \]

3. **Substitute the known values into the equation**:
\[ I = \frac{2 \, \text{V}}{1000 \, \Omega} \]

4. **Calculate the current**:
\[ I = \frac{2}{1000} = 0.002 \, \text{A} \]

5. **Convert the current to milliamperes**:
\[ I = 0.002 \, \text{A} = 2 \, \text{mA} \]

### Final Answer:
The current flowing through the 1 kΩ resistor when a potential difference of 2 V is applied is **2 mA**.