A biconvex lens with both faces of the same radius of curvature is to be manufactured from a glass of refractive index 1.55. What should be the radius of curvature for the focal length of the lens to be 20 cm ?

Explanation

To solve the problem, we will use the lens maker's formula, which is given by:

\[ \frac{1}{F} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \]

Where:
- \( F \) is the focal length of the lens,
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