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What is f in mirror formula (1)/(u)+(1)/...

What is f in mirror formula `(1)/(u)+(1)/(v)=(1)/(f)` ?

A

distance of object

B

distance of image

C

focal length

D

None.

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( f \) in the mirror formula \( \frac{1}{u} + \frac{1}{v} = \frac{1}{f} \), let's break it down step by step: ### Step 1: Understand the Mirror Formula The mirror formula relates the object distance \( u \), the image distance \( v \), and the focal length \( f \) of a mirror. The formula is given as: \[ \frac{1}{u} + \frac{1}{v} = \frac{1}{f} \] ### Step 2: Identify the Variables - \( u \): Object distance from the mirror (measured from the mirror to the object). - \( v \): Image distance from the mirror (measured from the mirror to the image). - \( f \): Focal length of the mirror (the distance from the mirror's surface to its focal point). ### Step 3: Rearranging the Formula To find \( f \), we can rearrange the mirror formula. Start by isolating \( \frac{1}{f} \): \[ \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \] ### Step 4: Finding Focal Length \( f \) Now, take the reciprocal of both sides to solve for \( f \): \[ f = \frac{1}{\left(\frac{1}{u} + \frac{1}{v}\right)} \] ### Step 5: Sign Conventions It is important to note the sign conventions used in optics. For mirrors: - The object distance \( u \) is taken as negative if the object is in front of the mirror (real object). - The image distance \( v \) is positive if the image is real and formed on the same side as the object. - The focal length \( f \) is negative for concave mirrors and positive for convex mirrors. ### Conclusion Thus, the focal length \( f \) in the mirror formula is derived as: \[ f = \frac{uv}{u + v} \] This gives us the focal length based on the object and image distances. ---
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The mirror formula is (1)/(f) = (1)/(v) + (1)/(u) where symbols have standard meaning. How will focal length of mirror change when u is changed by moving the object towards or away from the mirror?

When an object is placed normally on the principal axis of a spherial mirror at a distance 'a' from its pole, its image is formed at a distance 'v' from the pole of mirror such that (1)/(v)+(1)/(u)=(1)/(f) , where f = focal length of given mirror. The relation is called mirror formula and is true for all types of mirrors under all conditions. However, values of u, v and f must be put with proper signs are per the sign convention followed. If 'h' be the height of the linear object and h' the height of image, then ratio (h')/(h) is called linear magnification or lateral magnification and its value m is given as : m=(h')/(h)=-(v)/(u) What is the surface area of image of linear object formed by the given concave mirror?

Knowledge Check

  • The focal length of a less is given by the formula (1)/(f)=(1)/(u)+(1)/(v) . Make f as the subject of the formula. if u=20cm and v=30, then find f. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Given (1)/(f)=(1)/(u)+(1)/(v) (B) rArr f=(uv)/(u+v) (C) f=(20xx30)/(20+30)=(600)/(50)=12 cm. (D) rArr (1)/(f)=(v+u)/(uv)

    A
    ADBC
    B
    BADC
    C
    ACDB
    D
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  • Directions for questions : Select the correct answer from the given options. The focal length of a mirror is given by the formula (1)/(f) = (1)/(mu) + (1)/( v) . Make f fast the subject of the formula. If u = 20 "cm" and v = 30 "cm" , then find f . The following seeps are involved in solving the above problem. Arrange chem in sequential order. A Given (1)/(f) = (1)/( u ) + (1)/(v) B rArr f = (uv)/( u+v) C f = (20 xx 30)/( 20 + 30) = (600)/(50) = 12 cm D rArr (1)/( f) = (v+u)/( uv)

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    ADBC
    B
    BADC
    C
    ACDB
    D
    DBAC
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