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A 600pF capacitor is charged with 100 V...

A 600pF capacitor is charged with 100 V battery . Calculate the energy stored and charge on the capacitor .

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Find the charge stored in the capacitor.

Find the charge stored in the capacitor.

Knowledge Check

  • A 700 pF capacitor is charged by a 50 V battery. The electrostatic energy stored it is

    A
    `17.0xx10^(-8)J`
    B
    `13.6xx10^(-9)J`
    C
    `9.5xx10^(-9)J`
    D
    `8.7xx10^(-7)J`

  • A 900 pF capacitor is charged by a 100 V battery. The electrostatic energy stored by the capacitor is

    A
    `9xx10^(5)J`
    B
    `4.5xx10^(-6)J`
    C
    `2.2xx10^(-6)J`
    D
    `9xx10^(-10)J`

  • A capacitor of capacity 10muF is subjected to charge by a battery of 10 V. Calculate the energy stored in the capacitor.

    A
    `2xx10^(-7)J`
    B
    `3xx10^(-5)J`
    C
    `5xx10^(-4)J`
    D
    `8xx10^(-6)J`

    • Similar Questions

    Explore conceptually related problems

    Find the charge stored in the capacitor.

    A 900 pF capacitor is charged by 100V battery. (a) How much electrostatic energy is strored by the capacitor ? The capacitor is disconnected from the battery and connected to another 900 pF capacitor. How much is the electrostatic energy stored in the system ?

    A 900 pF capacitor is charged by 100 V battery. (i) How much electrostatic energy is stored by the capacitor ? (ii) The capacitor is disconnected from the battery and connected to another 900 pF capacitor What is the electrostatic energy stored by the system ?

    (a) A parallel plate capacitor has a capacity of 6muF , with air in between the plates and 60muF when dielectric medium is introduced. What is the dielectric constant (K) of the medium? (b) A 900 pF capacitor is charged by 100 V battery. (i) How much electrostatic energy is stored by the capacitor? (ii) The capacitor is now disconected from the battery and is connected to another uncharged 900 pF capacitor. How much is the electrostatic energy stored in the system?

    Assertion : When a capacitor is charged by a battery. Half of the energy supplied by the battery is stored in the capacitor and rest half is lost. Reason : If resistance in the circuit is zero, then there will be no loss of energy.

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