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A can do a piece of work in 5 days, B ca...

A can do a piece of work in 5 days, B can do it in 10 days. With the help of C, they finish the work in 2 days. In how many days C alone can do the whole work?

A

3

B

4

C

5

D

6

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break it down: ### Step 1: Determine the work done by A and B - A can complete the work in 5 days. Therefore, A's work rate (efficiency) is: \[ \text{Efficiency of A} = \frac{1 \text{ work}}{5 \text{ days}} = \frac{1}{5} \] - B can complete the work in 10 days. Therefore, B's work rate (efficiency) is: \[ \text{Efficiency of B} = \frac{1 \text{ work}}{10 \text{ days}} = \frac{1}{10} \] ### Step 2: Determine the combined work rate of A and B - The combined efficiency of A and B is the sum of their individual efficiencies: \[ \text{Efficiency of A + B} = \frac{1}{5} + \frac{1}{10} \] - To add these fractions, we need a common denominator. The least common multiple of 5 and 10 is 10: \[ \text{Efficiency of A + B} = \frac{2}{10} + \frac{1}{10} = \frac{3}{10} \] ### Step 3: Determine the combined work rate of A, B, and C - Together, A, B, and C complete the work in 2 days. Therefore, their combined efficiency is: \[ \text{Efficiency of A + B + C} = \frac{1 \text{ work}}{2 \text{ days}} = \frac{1}{2} \] ### Step 4: Find the efficiency of C - We can find C's efficiency by subtracting the combined efficiency of A and B from the combined efficiency of A, B, and C: \[ \text{Efficiency of C} = \text{Efficiency of A + B + C} - \text{Efficiency of A + B} \] \[ \text{Efficiency of C} = \frac{1}{2} - \frac{3}{10} \] - To perform this subtraction, we need a common denominator. The least common multiple of 2 and 10 is 10: \[ \text{Efficiency of C} = \frac{5}{10} - \frac{3}{10} = \frac{2}{10} = \frac{1}{5} \] ### Step 5: Determine the time taken by C to complete the work alone - Since C's efficiency is \(\frac{1}{5}\), the time taken by C to complete the entire work alone is the reciprocal of his efficiency: \[ \text{Time taken by C} = \frac{1}{\text{Efficiency of C}} = \frac{1}{\frac{1}{5}} = 5 \text{ days} \] ### Final Answer C alone can complete the work in **5 days**. ---
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ARIHANT SSC-TIME AND WORK-EXERCISE(LEVEL 1)
  1. A alone con finish a piece of work in 12 days and B alone can do it in...

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  2. A can do a piece of work in 10 days, B can do it in 12 days and C can ...

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  3. A can do a piece of work in 5 days, B can do it in 10 days. With the h...

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  4. A can do a piece of work in 8 days, B can do it in 16 days, while C ca...

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  5. A can do a piece of work in 10 days, B can do it in 15 days working to...

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  6. A can do a piece of work in 24 days, while B can do it in 30 days. Wit...

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  7. A can do a piece of work in 10 days. B can do it in 24 days. If C also...

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  8. A can do a piece of work in 14 days while B can do it in 21 days. In h...

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  9. A can do a piece of work in 24 days. If B is 60% more efficient than A...

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  10. A is twice as good a workman as B and together they finish a piece of ...

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  11. A is twice as good a workman as B and together they finish a piece of ...

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  12. A is thrice as good a workman as B and takes 10 days less to do a piec...

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  13. A is twice as good a workman as B and therefore A takes 6 days less th...

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  14. A is thrice efficient as B and C is twice as efficient as B. What is t...

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  15. Ajit is 3 times as efficient as Bablu, then the ratio of number of day...

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  16. X is 4 times more efficient as Y, then the number of days taken by X a...

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  17. If A takes 4//5 days as B takes and working together they require (20)...

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  18. A is thrice as efficient as B. Working together they complete the work...

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  19. A and B can do a piece of work in 8 days, B and C can do the same work...

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  20. A and B can do a piece of work in 12 days, B and C in 15 days and C an...

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