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20 persons completed (1)/(3)rd of the wo...

20 persons completed `(1)/(3)rd` of the work in 24 days. How many more person are required to finish the rest of the work in next 12 days?

A

20

B

12

C

18

D

40

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the concept of work done by a certain number of persons in a given number of days. ### Step 1: Determine the total work Given that 20 persons completed \( \frac{1}{3} \) of the work in 24 days, we can denote the total work as 1 unit. Therefore, the work done by 20 persons in 24 days is: \[ W_1 = \frac{1}{3} \] ### Step 2: Calculate the total work done by one person in one day The work done by 20 persons in 24 days can be expressed as: \[ \text{Work done by 20 persons in 24 days} = 20 \times 24 = 480 \text{ person-days} \] Since this is equal to \( \frac{1}{3} \) of the total work, we can find the total work in person-days: \[ \text{Total work in person-days} = 480 \times 3 = 1440 \text{ person-days} \] ### Step 3: Determine the remaining work The remaining work, which is \( W_2 \), is: \[ W_2 = 1 - \frac{1}{3} = \frac{2}{3} \] ### Step 4: Set up the equation for the remaining work Let \( x \) be the number of additional persons required. The total number of persons working to complete the remaining work will be \( 20 + x \). They need to complete \( \frac{2}{3} \) of the work in 12 days. The equation for work done can be set up as: \[ (20 + x) \times 12 = \frac{2}{3} \times 1440 \] ### Step 5: Calculate the right-hand side Calculating the right-hand side: \[ \frac{2}{3} \times 1440 = 960 \text{ person-days} \] ### Step 6: Substitute and solve for \( x \) Now substituting back into the equation: \[ (20 + x) \times 12 = 960 \] Dividing both sides by 12: \[ 20 + x = \frac{960}{12} = 80 \] Now, solving for \( x \): \[ x = 80 - 20 = 60 \] ### Conclusion Thus, the number of additional persons required to finish the remaining work in the next 12 days is: \[ \boxed{60} \] ---
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ARIHANT SSC-TIME AND WORK-EXERCISE(LEVEL 1)
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