Home
Class 11
PHYSICS
A mass m suspended by a spring, oscillat...

A mass m suspended by a spring, oscillates with frequency `f_(1)`. The same mass m oscillates with frequency `f_(2)` if length of the spring is made one-third. Find the ratio `f_(1)//f_(2)`.

Text Solution

AI Generated Solution

To solve the problem, we need to find the ratio of the frequencies \( f_1 \) and \( f_2 \) of a mass \( m \) suspended by a spring when the length of the spring is changed. ### Step-by-Step Solution: 1. **Understanding the Frequency of Oscillation**: The frequency of oscillation \( f \) for a mass \( m \) attached to a spring with spring constant \( k \) is given by the formula: \[ f = \frac{1}{2\pi} \sqrt{\frac{k}{m}} ...
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    MODERN PUBLICATION|Exercise Conceptual Questions|18 Videos
  • OSCILLATIONS

    MODERN PUBLICATION|Exercise TOUGH & TRICKY PROBLEMS|9 Videos
  • OSCILLATIONS

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS|15 Videos
  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos
  • PHYSICAL WORLD

    MODERN PUBLICATION|Exercise Revision exercises (Long answer questions)|6 Videos

Similar Questions

Explore conceptually related problems

The frequency of oscillations of a mass m suspended by a spring is v_(1) . If the length of the spring is cut to one-half the same mass oscillates with frequency v_(2) . Determine the value of v_(2)//v_(1)

The frequency of oscillation of a mass m suspended by a spring is v_(1) . If the length of the spring is cut to on-half, the same mass oscillates with frequency v_(2) . Determing the value of v_(2)//v_(1) .

The frequency of oscillations of a mass m suspended by spring of v_(1) . If the length of the spring is cut to one-third, the same mass oscillates with frequency v_(2) . Determing the value of v_(2)//v_(1)

Is oscillation of a mass suspended by a spring simple harmonic ?

A object of mass m is suspended from a spring and it executes SHM with frequency n. If the mass is increased 4 times , the new frequency will be

A block of mass m , when attached to a uniform ideal apring with force constant k and free length L executes SHM. The spring is then cut in two pieces, one with free length n L and other with free length (1 - n)L . The block is also divided in the same fraction. The smaller part of the block attached to longer part of the spring executes SHM with frequency f_(1) . The bigger part of the block attached to smaller part of the spring executes SHM with frequency f_(2) . The ratio f_(1)//f_(2) is

The frequency of oscillation of amass m suspended by a spring is v_(1) . If length of spring is cut to one third then the same mass oscillations with frequency v_(2) . Then

A mass m is vertically suspended from a spring of negligible mass, the system oscillates with a frequency n. what will be the frequency of the system, if a mass 4m is suspended from the same spring?

A mass m oscillates with simple harmonic motion with frequency f= omega/(2pi) and amlitude A on a spring with constant K. therefore

A spring has a force constant k and a mass m is suspended from it the spring is cut in two equal halves and the same mass is suspended from one of the halves. If the frequency of oscillation in the first case is n, then the frequency in the second case will be

MODERN PUBLICATION-OSCILLATIONS -PRACTICE PROBLEMS 2
  1. A spring of force constant 20 N/m is cut into four equal parts, All t...

    Text Solution

    |

  2. A mass m suspended by a spring, oscillates with frequency f(1). The sa...

    Text Solution

    |

  3. Find the effective force constant in the situation when infinite numbe...

    Text Solution

    |

  4. 5 N of force is required to stretch a spring by 3 cm. If the spring is...

    Text Solution

    |

  5. Calculate the elongation produced in each spring in the following case...

    Text Solution

    |

  6. A mass m is suspended from a weightless spring. The time period of osc...

    Text Solution

    |

  7. Two particles P(1) and P(2) having identical masses are suspended from...

    Text Solution

    |

  8. Calculate the frequency of oscillations of a mass m = 10 kg in the fol...

    Text Solution

    |

  9. A mass of 5 kg is attached to the free end of a spring pulled sideways...

    Text Solution

    |

  10. The ratio of Young's modulus of two springs of same area of cross sect...

    Text Solution

    |

  11. On compressing a spring by 0.5 m, a restoring force of 20 N is develop...

    Text Solution

    |

  12. Two spring of spring constants k(1) and k(2) ar joined and are connect...

    Text Solution

    |

  13. A pendulum clock shows accurate timings. IF the length of the pendulum...

    Text Solution

    |

  14. A second's pendulum is oscillating at a place where g = 9.8 m//s^(2). ...

    Text Solution

    |

  15. A second's pendulum is taken to a lift. Calculate the time period of o...

    Text Solution

    |

  16. If length of pendulum is increased by 2%. The time period will

    Text Solution

    |

  17. A simple pendulum has a time period T. The pendulum is completely imme...

    Text Solution

    |

  18. A sphere is hanged with a wire. A restoring torque of 5 Nm is produced...

    Text Solution

    |

  19. A wooden block of mass 20 gram and cross section 20 cm^(2) is floating...

    Text Solution

    |

  20. A glass tube is floating in a liquid with 30 cm of its length immersed...

    Text Solution

    |