A mass m is suspended from a weightless spring. The time period of oscillation of mass is 3 s . Calculate the value of m if on suspending an additional mass of 3kg, time period increases by 2 s.

Explanation

To solve the problem, we will use the formula for the time period of a mass-spring system, which is given by:

\[ T = 2\pi \sqrt{\frac{m}{k}} \]

where \( T \) is the time period, \( m \) is the mass, and \( k \) is the spring constant.

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