A second's pendulum is taken to a lift. Calculate the time period of oscillation of pendulum if the (a) lift it moving upwards with a = 4 `m//s^(2)` and (b) downwards with a = 3 `m//s^(2)`

Explanation

To solve the problem, we need to calculate the time period of a seconds pendulum in two scenarios: when the lift is moving upwards with an acceleration of 4 m/s² and when it is moving downwards with an acceleration of 3 m/s².

### Given:
- The time period of a seconds pendulum in an inertial frame (when the lift is at rest) is \( T_0 = 2 \) seconds.
- The acceleration due to gravity \( g = 10 \, \text{m/s}^2 \).

### Formula:
The time period \( T \) of a simple pendulum is given by:
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