A simple pendulum consists of an inextensible string of length L and mass M. The oscillating pendulum is suspended inside a stationary lift. The lift then started descending with an acceleration `3.4 m//s^(2)`. Will its time period increase, decrease or remain same?

Explanation

To solve the problem, we need to analyze the effect of the lift's acceleration on the time period of the simple pendulum. Let's break it down step by step.

### Step 1: Understand the Time Period of a Simple Pendulum
The time period \( T \) of a simple pendulum is given by the formula:
\[ T = 2\pi \sqrt{\frac{L}{g_{\text{effective}}}} \]
where \( L \) is the length of the pendulum and \( g_{\text{effective}} \) is the effective acceleration due to gravity acting on the pendulum bob.
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