A body is executing simple harmonic motion with time period of 3 s. After how much time interval (from t = 0) the displacement will be `(1)/(sqrt(2))` times of its amplitude ?

Explanation

To solve the problem step by step, we will follow the process of analyzing simple harmonic motion (SHM) and using the relevant equations.

### Step 1: Understand the parameters of SHM
The time period \( T \) of the motion is given as 3 seconds. We can denote the amplitude of the motion as \( A \).

**Hint:** The time period \( T \) is the time taken for one complete cycle of the motion.

### Step 2: Determine the angular frequency \( \omega \)
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