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A spring of force constant k is cut into...

A spring of force constant k is cut into two pieces whose lengths are in the ratio 1:2. The force constant of the longer piece?

A

`(1)/(2)K`

B

`(2)/(3)K`

C

`K/2`

D

`(3)/(2)K`

Text Solution

Verified by Experts

The correct Answer is:
D
Spring constant, `K = (F)/(x)`
Length of longer piece is `x. = (2x)/(3)`
`therefore` Force constant, `K. = (F)/(x) = (F)/(2x//3) = (3F)/(2x) = (3)/(2)K`
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