A body is executing simple harmonic motion under the action of a force `F_(1)` with time period 1 s. The time period is 2s when body is acted by another force `F_(3)`. What will be the total time period when both the forces are acting in same direction simultaneously ?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the relationship between force and time period
The time period \( T \) of a body executing simple harmonic motion (SHM) is related to the force acting on it. The relationship can be expressed as:
\[ T \propto \sqrt{\frac{1}{F}} \]
This means that the time period is inversely proportional to the square root of the force.
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